Question

If the mean deviation of the number $1,1+d,...1+100d$ from their mean is $255$, then $a$ value of $d$ is

• A. $10.1$
• B. $20.2$
• C. $10$
• D. $5.08$

Answer 1

The correct option is D $5.08$

$\begin{array}{c}1,1+d\\ 1+100d\\ 255=\frac{\frac{v}{2}\left(1+1+100d\right)}{N}\\ 255=\frac{1}{2}\left(2+100d\right)=1+50d\\ 255-1=50d\\ d=\frac{254}{50}=5.08\end{array}$