If the mean of 1- 2- 3-n is 6n-11- then n is

By the given condition n(n+1)/2n=6n/11 ⇒ 11n^2+11n=12n ⇒ n^2=11n ⇒ n=11 [∵ n ≠ 0] ...

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If the mean o...

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If the mean of 1, 2, 3,..........,n is $\frac{6 n}{11}$ , then n is

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