If the mean of $7$ , $9$ , $11$ , $13$ , $x$ , $21$ is $13$ , find the value of $x$ .

17

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71

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15

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20

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Solution

The correct option is C $17$
Mean $= \frac{Sum of terms in data}{Number of terms in data}$
Mean of the given numbers $= \frac{(7 + 9 + 11 + 13 + x + 21)}{6}$
$= \frac{(61 + x)}{6}$
Given, Mean = $13$
$∴$ $\frac{61 + x}{6} = 13$
$61 + x = 78$
$x = 17$
Hence, the answer is option $A$

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Similar questions

Q. Without adding, find the sum:
(i) (1 + 3 + 5 + 7 + 9 + 11 + 13)
(ii) (1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19)
(iii) (1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23)

Without adding find the sum

(i) 1 + 3 + 5 + 7 + 9

(ii) 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19

(iii) 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23

Q. Without adding, find the sum
(i)

1 + 3 + 5 + 7 + 9

(ii)

1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19

(iii)

1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23

Q. The average frequency is

18

. Find the missing frequency

f

Class Interval	Frequency
$11 - 13$	$7$
$13 - 15$	$6$
$15 - 17$	$9$
$17 - 19$	$13$
$19 - 21$	$f$
$21 - 23$	$5$
$23 - 25$	$4$

The following distribution shows the daily pocket allowance of children of a locality. If the mean pocket allowance is Rs. 18, find the missing frequency f.
$\begin{matrix} Daily pocket allowance(in Rs) & 11 - 13 & 13 - 15 & 15 - 17 & 17 - 19 & 19 - 21 & 21 - 23 & 23 - 25 Frequency & 7 & 6 & 9 & 13 & f & 5 & 4 \end{matrix}$

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If the mean of 7,9,11,13,x,21 is 13, find the value of x.

The correct option is C 17Mean =Sum of terms in dataNumber of terms in dataMean of the given numbers =(7+9+11+13+x+21)6 =(61+x)6Given, Mean = 13 ∴ 61+x6=1361+x=78x=17Hence, the answer is option A

If the mean of $7$ , $9$ , $11$ , $13$ , $x$ , $21$ is $13$ , find the value of $x$ .

The correct option is C $17$
Mean $= \frac{Sum of terms in data}{Number of terms in data}$
Mean of the given numbers $= \frac{(7 + 9 + 11 + 13 + x + 21)}{6}$
$= \frac{(61 + x)}{6}$
Given, Mean = $13$
$∴$ $\frac{61 + x}{6} = 13$
$61 + x = 78$
$x = 17$
Hence, the answer is option $A$