If the mean of binomial distribution is - then the variance lies in the interval

The correct option is C [ 0,μ ] Given, #160; np=μ we know, variance #160; =npq=μ q and 0≤ q ≤ 1 Hence, range of variance is [0,μ] ...

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Probability Distribution

If the mean o...

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If the mean of binomial distribution is $μ$ , then the variance lies in the interval

[μ, 0]

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[0, \frac{μ}{2}]

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[0, μ]

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[0, \sqrt{μ}]

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If $μ$ is the mean of a distribution, then $\sum f_{i} (y_{i} - μ)$ is equal to

4 x^{2} - x - 1 = 0

3 x^{2} + (λ + μ) x + λ - μ = 0

λ

μ

λ

μ

If $μ$ is the mean of a distribution, then $\sum f_{i} (y_{i} - μ)$ is equal to

| {log}_{2} x + 1 | + ∣ ∣ 1 - ({log}_{2} x)^{2} ∣ ∣ = ∣ ∣ {log}_{2} x + ({log}_{2} x)^{2} ∣ ∣,

x

{λ} \cup [μ, \infty) .

| {log}_{2} x + 1 | + | 1 - {log}_{2}^{2} x | = | {log}_{2} x + {log}_{2}^{2} x |,

x

{λ} \cup [μ, \infty) .

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