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Question

If the mean of the data is 60, find the value of p.

Class markfrequency2535123545164555p55651565758758519859513
  1. 17

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Solution

The correct option is A 17

We know that,
Mean=fixifi

Now,
Class mark(xi)Frequency(fi)(xifi)3012360401664050p50p60159007085608019152090131170

So,
fi=83+p

fixi=5150+50p

Now,
fixifi=Mean
5150+50p83+p=60
5150+50p=4980+60p
170=10p
p=17

Hence, the value of p is 17.


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