If the mean of the data is 60 - find the value of p beginarray - WhineClass interval - frequency lilhline 25-35 - 12 Wlhline35-45 - 16 Wlhline45-55 - p Whline55-65 - 15 Whline 65-75 - 8 Whline75-85 - 19 Whline85-95 - 13 Whline lendarray -2 MARKS-

Concept: 1 Mark Application: 1 Mark [ Class Interval amp; Frequency amp; Cumulative Frequency; 30 ...

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Standard X

Mathematics

Frequency

If the mean o...

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If the mean of the data is 60, find the value of p

$\begin{matrix} C l a s s i n t e r v a l & f r e q u e n c y 25 - 35 & 12 35 - 45 & 16 45 - 55 & p 55 - 65 & 15 65 - 75 & 8 75 - 85 & 19 85 - 95 & 13 \end{matrix}$ [2 MARKS]

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Concept: 1 Mark
Application: 1 Mark

$\begin{matrix} C l a s s I n t e r v a l & F r e q u e n c y & C u m u l a t i v e F r e q u e n c y 30 & 12 & 360 40 & 16 & 640 50 & p & 50 p 60 & 15 & 900 70 & 8 & 560 80 & 19 & 1520 90 & 13 & 1170 \end{matrix}$

$\sum f_{i} = 83 + p$

$\sum f_{i} x_{i} = 5150 + 50 p$

$\frac{5150 + 50 p}{83 + p} = 60$

$5150 + 50 p = 4980 + 60 p$

$170 = 10 p$

$p = 17$

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If the mean of the data is 60, find the value of p

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\begin{matrix} C l a s s I n t e r v a l & F r e q u e n c y 25 - 35 & 1 35 - 45 & 5 45 - 55 & 5 55 - 65 & 4 65 - 75 & 0 75 - 85 & 8 85 - 95 & 2 T o t a l & 25 \end{matrix}

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If the mean of the data is 60, find the value of p Class intervalfrequency25−351235−451645−55p55−651565−75875−851985−9513 [2 MARKS]

Concept: 1 Mark Application: 1 Mark Class IntervalFrequencyCumulative Frequency3012360401664050p50p60159007085608019152090131170 ∑fi=83+p ∑fixi=5150+50p 5150+50p83+p=60 5150+50p=4980+60p 170=10p p=17

If the mean of the data is 60, find the value of p

$\begin{matrix} C l a s s i n t e r v a l & f r e q u e n c y 25 - 35 & 12 35 - 45 & 16 45 - 55 & p 55 - 65 & 15 65 - 75 & 8 75 - 85 & 19 85 - 95 & 13 \end{matrix}$ [2 MARKS]