If the mean of the data is 60, find the value of p
Class markfrequency25−351235−451645−55p55−651565−75875−851985−9513
17
Class mark(xi)Frequency(fi)(xifi)3012360401664050p50p60159007085608019152090131170
Mean = ∑fixi∑fi
∑fi=83+p
∑fixi=5150+50p
5150+50p83+p=60
5150+50p=4980+60p
170=10p
p=17