If the mean of the distribution is 2.6, then the value of y is:
$\begin{matrix} Variable x & 1 & 2 & 3 & 4 & 5 Frequency of x & 4 & 5 & Y & 1 & 2 \end{matrix}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 8
We know that Mean
$= \frac{n \sum i = 1 f_{1} x_{1}}{n \sum i = 1}$
$i . e ., 2.6 = \frac{1 \times 4 + 2 \times 5 + 3 \times y + 4 \times 1 + 5 \times 2}{4 + 5 + y + 1 + 2}$
or $31.2 + 2.6 y = 28 + 3 y$
or $0.4 y = 3.2$
$\Rightarrow y = 8.$

Suggest Corrections

Similar questions

\begin{matrix} Variable x & 1 & 2 & 3 & 4 & 5 Frequency of x & 4 & 5 & Y & 1 & 2 \end{matrix}

Variable (x):	1	2	3	4	5
Frequency	4	5	y	1	2

2.6

$x_{i}$	1	2	3	4	5
$f_{i}$	5	4	f	2	3

\begin{matrix} V a r i a b l e (x) & 1 & 2 & 3 & 4 & 5 F r e q u e n c y & 4 & 5 & y & 1 & 2 \end{matrix}

Variate X	1	2	3	4	5
Frequency of X	4	5	k	1	2

Join BYJU'S Learning Program