If the mean of the distribution is 2-6- then the value of y is- Variable x 1 2 3 4 5- Frequency of x 4 5 Y 1 2- -

We know that Mean =∑^n_i=1f_1x_1/∑^n_i=1 i.e., 2.6 =1×4+2×5+3× y+4×1+5×2/4+5+y+1+2 or 31.2+2.6y=28+3y or 0.4y=3.2 ⇒ y=8. ...

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Standard XIII

Mathematics

Mean

If the mean o...

Question

If the mean of the distribution is 2.6, then the value of y is:
$\begin{matrix} Variable x & 1 & 2 & 3 & 4 & 5 Frequency of x & 4 & 5 & Y & 1 & 2 \end{matrix}$

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Solution

The correct option is C 8
We know that Mean
$= \frac{n \sum i = 1 f_{1} x_{1}}{n \sum i = 1}$
$i . e ., 2.6 = \frac{1 \times 4 + 2 \times 5 + 3 \times y + 4 \times 1 + 5 \times 2}{4 + 5 + y + 1 + 2}$
or $31.2 + 2.6 y = 28 + 3 y$
or $0.4 y = 3.2$
$\Rightarrow y = 8.$

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If the mean of the distribution is 2.6, then the value of y is: Variable x12345Frequency of x45Y12

The correct option is C 8We know that Mean =n∑i=1f1x1n∑i=1 i.e., 2.6 =1×4+2×5+3×y+4×1+5×24+5+y+1+2 or 31.2+2.6y=28+3y or 0.4y=3.2 ⇒y=8.

If the mean of the distribution is 2.6, then the value of y is:
$\begin{matrix} Variable x & 1 & 2 & 3 & 4 & 5 Frequency of x & 4 & 5 & Y & 1 & 2 \end{matrix}$

The correct option is C 8
We know that Mean
$= \frac{n \sum i = 1 f_{1} x_{1}}{n \sum i = 1}$
$i . e ., 2.6 = \frac{1 \times 4 + 2 \times 5 + 3 \times y + 4 \times 1 + 5 \times 2}{4 + 5 + y + 1 + 2}$
or $31.2 + 2.6 y = 28 + 3 y$
or $0.4 y = 3.2$
$\Rightarrow y = 8.$