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Question

If the mean of the following distribution is 6, find the value of p.
x:24610p+5
f:32312

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Solution

xi

fi

fixi

2 3 6
4 2 8
6 3 18
10 1 10

N=fi=11fixi=2(p+5)

We have, N=fi=11,fixi=2p+52
Mean = fixiN=62p+521166=2p+522p=14p=7

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