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Question

If the mean of the following distribution is 6, then value of p is
x:2 4 6 10 p+5
f:3 2 3 1 2

A
5
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B
7
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C
6
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D
12
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Solution

The correct option is B 7
6=(2×3)+(4×2)+(6×3)+(10×1)+(p+5)×23+2+3+1+2

6=6+8+18+10+2p+1011
6=52+2p11
6×11=52+2p
6652=2p
14=2p
p=142
p=7

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