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Question

If the mean of the following frequency distribution is 24, find the value of p. [CBSE 2013]
Class 0−10 10−20 20−30 30−40 40−50
Frequency 3 4 p 3 2

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Solution

The given data is shown as follows:
Class Frequency (fi) Class mark (xi) fixi
0−10 3 5 15
10−20 4 15 60
20−30 p 25 25p
30−40 3 35 105
40−50 2 45 90
Total ∑ fi = 12 + p ∑ fixi = 270 + 25p

The mean of given data is given by

x¯=ifixiifi24=270+25p12+p24(12+p)=270+25p288+24p=270+25p25p-24p=288-270p=18

Hence, the value of p is 18.

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