If the mean of the following frequency distribution is 54, find the value of p.
Class0−2020−4040−6060−8080−100Frequency7p10913
The given data is shown as follows:
Class | Frequency (fi) | Class mark (xi) | (fixi) |
0 - 20 | 7 | 10 | 70 |
20 - 40 | p | 30 | 30p |
40 - 60 | 10 | 50 | 500 |
60 - 80 | 9 | 70 | 630 |
80 - 100 | 13 | 90 | 1170 |
Total | ∑fi=39+p | ∑(fi×xi)=2370+30p |
The mean of given data is given by
¯x= ∑(fi×xi)/∑fi
⇒ 54 = 2370+30p39+p
⇒ 54(39 + p) = 2370 + 30p
⇒ 2106 + 54p = 2370 + 30p
⇒ 54p - 30p = 2370-2106
⇒ 24p = 264
⇒ p = 11
Hence, the value of p is 11.