If the mean of the given data is 25, then find the value of p.
Class intervalFrequency0−101010−20920−30830−40p40−506 [2 MARKS]
Concept: 1 Mark
Application: 1 Mark
Class MarkFrequencyfixi5105015913525820035p35p456270
∑fi=33+p
∑fixi=655+35p
Mean =25=655+35p33+p
825+25p=655+35p
10p=170
p=17