If the mean of the given data is 250, then find the value of p.
Class interval Frequency0−1007100−20011200−30015300−400p400−5008 [2 MARKS]
Concept: 1 Mark
Application: 1 Mark
Class MarksFrequencyfixi507350150111650250153750350p350p45083600
∑fi=41+p and ∑fixi=9350+350p
9350+350p41+p=250
9350+350p=10250+250p
100p=900
p=9