Question

If the mean of the numbers $27+x,31+x,89+x,107+x,156+xis82$, then the mean of $130+x,126+x,68+x,50+x,1+x$ is

• A. $75$
• B. $157$
• C. $82$
• D. $80$

Answer 1

Answer: (A)

$75$

Given, $82$ $=$ $\frac{27+x+31+x+89+x+107+x+156+x}{5}$
$\therefore$ $82\times 5=410+5x$
$\therefore$ $x=0$
Therefore, required mean is
Mean $=$ $\frac{130+x+126+x+68+x+50+x+1+x}{5}$
Mean $=$ $\frac{375+5x}{5}$ $=$ $\frac{375+0}{5}$ $=75$