If the mean of the set of numbers x1,x2,....xn is ¯x, then the mean of the numbers xi+2i,1≤i≤n is
¯x+2n
¯x+n+1
¯x+2
¯x+n
¯x=∑ni=1xin⇒∑ni=1xi=n¯x ∴∑ni=1(xi+2i)n=∑ni=1xi+2(1+2+...+n)n=n¯x+2n(n+1)2n=¯x+(n+1)
For the given distinct values x1,x2,x3,.....xn occurring with frequencies f1,f2,f3,...fn respectively. The mean deviation about mean where ¯¯¯x is the mean and N is total number of observations would be