You visited us 1 times! Enjoying our articles? Unlock Full Access!

Mean

If the mean o...

Question

If the mean of variate X in distribution 2.6, then the value of k is
Variate X 1 2 3 4 5
Frequency of X 4 5 k 1 2

8

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

10

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12

No worries! We‘ve got your back. Try BYJU‘S free classes today!

18

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $8$
$\frac{1 \times 4 + 2 \times 5 + 3 \times k + 4 \times 1 + 5 \times 2}{4 + 5 + k + 1 + 2} = 2.6$
$\Rightarrow 0.4 k = 3.2 \Rightarrow k = 8$

Suggest Corrections

Similar questions

Variate x	1	2	3	4	5
Frequency of x	4	5	k	1	2

Variable (x):	1	2	3	4	5
Frequency	4	5	y	1	2

Variate X	1	2	3	4	5
Frequency of X	4	5	k	1	2

X

2.6

k

8

^{'} k^{'}

$x$	$2$	$4$	$6$	$8$	$10$	$12$
$f r e q u e n c y = f$	$4$	$7$	$10$	$16$	$k$	$3$

\begin{matrix} V a r i a t e & 6 & 7 & 1.9 & 9 & 10 F r e q u e n c y & 1 & 2 & k & 3 & 4 \end{matrix}

3.6

k

Join BYJU'S Learning Program