Question

If the measure of an angle is $62$ ${}^o$, what is the measure of its complementary angle?

Answer 1

The sum of two complementary angle is ${90}^{\circ }$

one angle is given ${62}^{\circ }$

Let the other angle be $x$

$x+{62}^{\circ }={90}^{\circ }$

$x={90}^{\circ }-{62}^{\circ }$

$x={28}^{\circ }$