If the median AD of triangle ABC makes an angle - -4 with the side BC-then find the value of - B - C -

By m n theorem, #160; (BD+DC)π/4= DC B BD C ⇒ 2BD = BD | B C | #160; #160; #160; [∵ BD=DC] ⇒ | B C |= 2 ...

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Standard XII

Mathematics

Solution of Triangle

If the median...

Question

If the median AD of triangle ABC makes an angle $π / 4$ with the side BC,then find the value of $| cot B - cot C |$

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Solution

By $m - n$ theorem,
$(B D + D C) cot \frac{π}{4} = D C cot B - B D cot C$
$\Rightarrow 2 B D = B D | cot B - cot C | [∵ B D = D C]$
$\Rightarrow | cot B - cot C | = 2$

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If the median AD of triangle ABC makes an angle π/4 with the side BC,then find the value of |cotB−cotC|

By m−n theorem, (BD+DC)cotπ4=DCcotB−BDcotC⇒2BD=BD|cotB−cotC|[∵BD=DC]⇒|cotB−cotC|=2

If the median AD of triangle ABC makes an angle $π / 4$ with the side BC,then find the value of $| cot B - cot C |$

By $m - n$ theorem,
$(B D + D C) cot \frac{π}{4} = D C cot B - B D cot C$
$\Rightarrow 2 B D = B D | cot B - cot C | [∵ B D = D C]$
$\Rightarrow | cot B - cot C | = 2$