Question

If the median of $20,25,28,x,33,34$ is $29$, then the maximum possible value of $x$ is

• A. $30$
• B. $31$
• C. $29$
• D. $32$

Answer 1

Answer: (A)

$30$

$20,25,28,x,33,34$.

Total number of terms including $x$ is $6$.
Hence median will be mean of $3^{rd}$ and $4^{th}$ term.
$\therefore 29=\frac{x+28}{2}\Rightarrow x=30$