Question

If the median of 33, 28, 20, 25, 34, x is 29, find the maximum possible value of x.

Answer 1

Median of 33, 28, 20, 25, 34, x is 29.

Now, arranging in ascending order 20, 25, 28, x, 33, 34

Here n = 6

$\therefore$ Median $=\frac{1}{2}$[3rd term + 4th term]

29 = $\frac{1}{2}[28+x]$

58 = 28 + x $\Rightarrow$ x = 58 - 28 = 30

$\therefore$ Possible value of x = 30