If the median of the following data is 166-79- then the mean and mode are Class interval Frequency 130-140 5 140-150 9 150-160 17 160-170 28 170-180 24 180-190 10 190-200 7

The correct option is A Mode = 167.3, Mean = 168.03 Hence, Mode = 167.3, Mean = 168.03 ...

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Standard X

Mathematics

Direct Method of Finding Mean

If the median...

Question

If the median of the following data is 166.79, then the mean and mode are

Mode = 161.9 Mean = 168

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Mode = 167.3, Mean = 168.03

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Mode = 152.9 Mean = 166.73

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Mode = 160.9 Mean = 167

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Solution

The correct option is B
Mode = 167.3, Mean = 168.03

\

Hence, Mode = 167.3, Mean = 168.03

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Q. In a city, the weekly observations made on the cost of living index are given below.

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Represent the above information in the form of a histogram.

Q. Compute the mean deviation from the median and from the mean for the following distribution of the scores of 50 college students:

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Q. The following table gives distribution of marks for 50 students of a class. Calculate mean deviation from the mean and median respectively from the data:

Marks Obtained	140−150	150−160	160−170	170−180	180−190	190−200
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Find the mode of the following data.
$\begin{matrix} C l a s s i n t e r v a l & 100 - 120 & 120 - 140 & 140 - 160 & 160 - 180 & 180 - 200 F r e q u e n c y & 10 & 13 & 8 & 7 & 12 \end{matrix}$

Find the mean, using assumed-mean method:

$\begin{matrix} Class & 100 - 120 & 120 - 140 & 140 - 160 & 160 - 180 & 180 - 200 Frequency & 10 & 20 & 30 & 15 & 5 \end{matrix}$

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If the median of the following data is 166.79, then the mean and mode are

The correct option is B Mode = 167.3, Mean = 168.03 \ Hence, Mode = 167.3, Mean = 168.03

The correct option is B
Mode = 167.3, Mean = 168.03

\

Hence, Mode = 167.3, Mean = 168.03