If the median of the following data is 50, then find p.
Class0-2020-4040-6060-8080-100Frequency10716p8
9
Class FrequencyCumulative Frequency0-20101020-4071740-60163360-80p33+p80-100841+p
Since median is 50, median class is 40-60.
n2=(41+p)2
median = 40 + [(41+p)2−1716×20] = 50
[(41+p)2−1716×20] = 10
Simplifying, we get (41+p)2 = 25
Or, p = 9