If the median of the following data is 50, then find p.
Class0-2020-4040-6060-8080-100Frequency10716p8
9
ClassFrequencyCumulative Frequency0-20101020-4071740-60163360-80p33+p80-100841+p
Since median is 50, median class is 40-60.
N2=(41+p)2
Median=40+[(41+p)2−1716×20]=50
[(41+p)2−1716×20]=10⇒(41+p)2=25
p = 9