If the middle point of a chord of the circle x2+y2+x−y−1=0 be (1,1), then the length of the chord is
4
2
5
5/2
Here radius of circle is
AC=√(12)2+(12)2+1=√32
and CB=√(0)2+(12)2=(12)
Now AB2=AC2−BC2=32−14=54
∴lengthofchordis52
From origin, chords are drawn to the circle x2+y2−2y=0.The locus of the middle points of these chords is
From the origin chords are drawn to the circle (x−1)2+y2=1. The equation of the locus of the middle points of these chords is