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Question

If the middle term in the expansion of (x2+2)8is 1120; then xR is equal to

A
2
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B
3
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C
3
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D
2
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Solution

The correct options are
A 2
D 2
Here n is even
Middle term is (n2+1)th(4+1)th,i.e.,T5
T5= 8C4(x2)424=1120 8C4x4=87651234x4=1120
x4=112070=16
x416=0
(x2+4)(x24)=0
x=±2 as xR

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