Question

If the midpoints of the line segment joining the points $P(6,b-2)$ and $(-2,4)$ is $(2,-3),$ find the value of $b.$

Answer 1

$P(6,b-2),Q=(-2,4)$

midpoint of PQ is $(2,-3)$

$x=2$ $y=-3$

$y=\frac{y_1+y_2}{2}$, Acording to midpoint formula

$-3=\frac{b-2+4}{2}$

$-6=b+2$

$\therefore b=-8$