Question

If the modulation index of on AM wave is changed from 0 to 1, then the transmitted power is increased by _______ %

• A. 50

Answer 1

The correct option is A 50

$P=P_c(1+\frac{{\mu }^2}{2})$

$P=P_{c}for\mu =0$

$P=\frac{3}{2}{P}_{c}for\mu =1$

$\therefore \frac{\Delta P_c}{P_c}=\frac{1}{2}\times 100=50$