If the moduli of the vectors a, b, c are 3, 4, 5 respectively and a and b + c, b and c + a, c and a + b are mutually perpendicular, then the modulus of a + b + c is
A
√12
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B
12
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C
5√2
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D
50
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Solution
The correct option is C 5√2 According to the given comdition, a.(b+c)=0.....(i) b.(c+a)=0.....(ii) c.(a+b)=0.....(iii) Now adding (i),(ii) and (iii),we get 2(a.b+b.c+c.a)=0.{∵ a.b=b.a etc.} Hence,|a+b+c|2=a2+b2+c2+2(a.b+b.c+c.a) =32+42+52 ⇒|a+b+c|=√50=5√2.