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Question

If the moduli of the vectors a, b, c are 3, 4, 5 respectively and a and b + c, b and c + a, c and a + b are mutually perpendicular, then the modulus of a + b + c is

A
√12
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B
12
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C
5√2
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D
50
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Solution

The correct option is C 5√2
According to the given comdition,
a.(b+c)=0 .....(i)
b.(c+a)=0 .....(ii)
c.(a+b)=0 .....(iii)
Now adding (i),(ii) and (iii),we get
2(a.b+b.c+c.a)=0.{ a.b=b.a etc.}
Hence,|a+b+c|2=a2+b2+c2+2(a.b+b.c+c.a)
=32+42+52
|a+b+c|=50=52.

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