If the molar heat capacity of a gas in the process $P T = c o n s t a n t i s 5 R$ , the number of degrees of freedom of molecules in the gas is

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $6$
Given that PT $=$ k
$Δ$ C $= 5$ R
$C = C_{v} + 2 R$
$C_{v} = \frac{R}{r - 1}$
$3 R = \frac{R}{r - 1}$
$(r - 1) = \frac{1}{3}$ ……….. $(1)$
$f = \frac{2}{(r - 1)}$
$= \frac{2}{(1 / 3)} = 6$ .

Suggest Corrections

Similar questions

C = 37.35 J {mol}^{- 1} K^{- 1}

P T = constant

C = 29 J m o l^{- 1} K^{- 1}

C = 37.55

m o l e^{- 1} K^{- 1}

=

γ

C_{P} = 29 J m o l^{- 1} K^{- 1}

Join BYJU'S Learning Program