Question

If the molar mass of glucose is 180 gram calculate the mass percentage of all its constituents of atoms

Answer 1

Molar mass of Glucose, C₆H₁₂O₆ = 180 g mol^-1
​Mass % can be calculated as
= ( Mass of element / Molar mass)$\times$100
Mass % of Carbon = [(6$\times$12) / (180)]$\times$100
= 40
Mass % of Oxygen = [(6$\times$16) / (180)]$\times$100
= 53.33
Mass % of hydrogen = [(12$\times$1) / 180]$\times$100
= 6.67