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Stoichiometry

If the mole f...

Question

If the mole fraction of iodine in benzene is $0.25$ , then what will be the molality of the solution?

A

3.27 m

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B

5.27 m

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C

4.27 m

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D

7.27 m

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Solution

The correct option is C $4.27 m$
Taking a basis of 1 mol of solution,
$n_{s o l u t e} + n_{s o l v e n t} = 1$
The solute here is iodine and the solvent is benzene.
$n_{i o d i n e} = 0.25 n_{b e n z e n e} = 0.75$
Mass of benzene:
$= 0.75 \times 78 = 58.5 g m = 0.0585 k g$
$M o l a l i t y (m) = \frac{n_{s o l u t e}}{W_{s o l v e n t} (i n k g)} = \frac{0.25}{0.0585} = 4.27 m$

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