If the molecular weight of two gases are $M_{1}$ and $M_{2}$ , then at a given tempreture the ratio of their root mean square velocity $v_{1}$ and $v_{2}$ will be

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Solution

The correct option is B

$v = \sqrt{\frac{3 R T}{M}}$

$\frac{v_{1}}{v_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}$

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If the molecular weight of two gases are M1 and M2, then at a given tempreture the ratio of their root mean square velocity v1 and v2 will be

The correct option is B v=√3RTM v1v2=√M2M1

If the molecular weight of two gases are $M_{1}$ and $M_{2}$ , then at a given tempreture the ratio of their root mean square velocity $v_{1}$ and $v_{2}$ will be

The correct option is B

$v = \sqrt{\frac{3 R T}{M}}$

$\frac{v_{1}}{v_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}$