If the momentum of an electron is changed by P, then the de-Broglie wavelength associated with it changes by 0.5%. The initial momentum of electron will be:

200P

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400P

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$\frac{P}{200}$

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100P

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Solution

The correct option is A
200P

$λ = \frac{h}{p}$ [de -Brogli wavelength]
$P = \frac{h}{λ} \frac{Δ P}{P} = - \frac{Δ λ}{λ} \frac{P}{P_{i n i t i a l}} = \frac{0.5}{100} P_{i n i t i a l} = 200 P$

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If the momentum of an electron is changed by P, then the de-Broglie wavelength associated with it changes by 0.5%. The initial momentum of electron will be:

The correct option is A 200P λ=hp[de -Brogli wavelength] P=hλΔPP=−ΔλλPPinitial=0.5100Pinitial=200P

The correct option is A
200P

$λ = \frac{h}{p}$ [de -Brogli wavelength]
$P = \frac{h}{λ} \frac{Δ P}{P} = - \frac{Δ λ}{λ} \frac{P}{P_{i n i t i a l}} = \frac{0.5}{100} P_{i n i t i a l} = 200 P$