If the momentum of an electron is changed by $P$ , then the de-Broglie wavelength associated with it changes by $0.5$ . The initial momentum of electron will be :

400 P

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\frac{P}{200}

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100 P

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200 P

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Solution

The correct option is B $200 P$
Initial momentum, $P_{i} = \frac{h}{λ}$
or
$P_{i} - P = \frac{h}{λ + \frac{0.5}{100} λ}$
or
$P_{i} - P = \frac{P_{i}}{\frac{1005}{1000}}$
or
$P_{i} = \frac{1005 P}{5} \approx 200 P$

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If the momentum of an electron is changed by P, then the de-Broglie wavelength associated with it changes by 0.5. The initial momentum of electron will be :

The correct option is B 200PInitial momentum, Pi=hλ orPi−P=hλ+0.5100λorPi−P=Pi10051000orPi=1005P5≈200P

If the momentum of an electron is changed by $P$ , then the de-Broglie wavelength associated with it changes by $0.5$ . The initial momentum of electron will be :

The correct option is B $200 P$
Initial momentum, $P_{i} = \frac{h}{λ}$
or
$P_{i} - P = \frac{h}{λ + \frac{0.5}{100} λ}$
or
$P_{i} - P = \frac{P_{i}}{\frac{1005}{1000}}$
or
$P_{i} = \frac{1005 P}{5} \approx 200 P$