If the mth, nth and pth terms of an AP and GP be equal and be respectively x, y, z, then
A
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B
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C
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D
None of the these
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Solution
The correct option is A A+(m−1)d=xA+(n−1)d=yA+(p−1)d=z⇒x−ym−n=y−zn−pAndARm−1=xARn−1=yARp−1=y⇒Rm−1=xyandRn−p=xz From Eqs.(i)and(ii),we get [xy]y−z=[yz]x−y