If the $n^{t h}$ term of an A.P. is given by $a_{n} = 5 n - 3$ , then the sum of first $10$ terms is

225

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245

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255

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270

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Solution

The correct option is B $245$
Putting $n = 1, 10,$ we get $a = 2, l = 47.$
$S_{10} = \frac{10}{2} (2 + 47) = 5 \times 49 = 245.$

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n^{t h}

t_{n} = 3 - 5 n

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Find the sum of first $24$ terms of the A.P. whose $n^{t h}$ term is given by $a_{n} = 3 + 2 n$

2 n^{2} + 5 n

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