If the nth term of the sequence is given by n3-1-n-1- then the sum of first n terms of the sequence is given byA- nn-1n-2-nB- nn2-2-3C- nD- nn-1n-2-2

The correct option is B n^th term of the sequence = (n^3+1)/(n+1) = n^2 n + 1 = [n(n+1)(2n+1)/6] [n(n+1)/2] + n = n(n^2+2)/3 ...

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If the nth te...

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If the $n^{t h}$ term of the sequence is given by $\frac{(n^{3} + 1)}{(n + 1)}$ , then the sum of first n terms of the sequence is given by

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