If the nitrogen atom had electronic configuration 1s7, it would have energy lower than that of the normal ground state configuration 1s22s22p3, because the electrons would be closer to the nucleus. Yet 1s7 is not observed because it violates:
A
Heisenberg's uncertainty principle
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B
Hund's rule
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C
Pauli's exclusion principle
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D
Bohr postulate of stationary orbits
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Solution
The correct option is C Pauli's exclusion principle
As per Pauli exclusion principle " no two electrons in the same atom can have all the four quantum numbers equal or an orbital cannot contain more than two electrons and it can accommodate two electrons only when their directions of spins are opposite".