If the normal at the point ′t′1 to the rectangular hyperbola xy=c2 meets it again at the point ′t′2 then the value of t1t2 is:
A
−t−11
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B
−t−21
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C
−t−31
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D
−t−41
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Solution
The correct option is B−t−21 Equation of normal of xy=c2att1 is y−ct1=t21(x−ct1) As it also passes through t2, ct2−ct1=t21(ct2−ct1) ⇒t1t2=−t−21 Hence, option 'B' is correct.