If the normal from the origin to the line xcos-ysin-p meets it at the point P-2-9- then p is equal to

In normal form of line , nbsp;xcosα+ysinα=p Distance from origin to point P is p So p is √(4+81)=√(85) ...

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Standard XII

Mathematics

Angle between Two Planes

If the normal...

Question

If the normal from the origin to the line $x cos α + y sin α = p$ meets it at the point $P (- 2, 9)$ , then $p$ is equal to

85

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\sqrt{85}

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\frac{1}{\sqrt{85}}

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1

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Solution

The correct option is B $\sqrt{85}$
In normal form of line , $x cos α + y sin α = p$
Distance from origin to point $P$ is $p$
So $p$ is $\sqrt{4 + 81} = \sqrt{85}$

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If the normal from the origin to the line xcosα+ysinα=p meets it at the point P(−2,9), then p is equal to

The correct option is B √85In normal form of line , xcosα+ysinα=p Distance from origin to point P is p So p is √4+81=√85

If the normal from the origin to the line $x cos α + y sin α = p$ meets it at the point $P (- 2, 9)$ , then $p$ is equal to

The correct option is B $\sqrt{85}$
In normal form of line , $x cos α + y sin α = p$
Distance from origin to point $P$ is $p$
So $p$ is $\sqrt{4 + 81} = \sqrt{85}$