If the normal to the rectangular hyperbola xy=c2 at the point (t1) meets the curve again at the point (t2), then
A
t31t2=1
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B
t31t2=−1
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C
t1t32=−1
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Solution
The correct option is Bt31t2=−1 If the normal to the rectangular hyperbola xy=c2 at the point (t1) meets the curve again at the point (t2), then t31t2=−1