If the normals at three points P,Q,R of the parabola y2=4ax meet at (b,c) then the centriod of the triangle PQR lies on the
A
axis of the parabola
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B
directrix of the parabola
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C
tangent at the vertex
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D
director circle
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Solution
The correct option is A axis of the parabola Equation of the normal to the parabola y2=4ax is y=mx−2am−am3 it passes through (b,c) ∴c=mb−2am−am3am3+(2a−b)m+c=0 Let the roots of the equation are m1,m2,m3 Then m1+m2+m3=0m1m2+m3m2+m1m3=2a−bam1m2m3=−ca Feet of the normals are P≡(am21,−2am1) Q≡(am22,−2am2) R≡(am23,−2am3) y coordinate of the centriod of the triangle PQR is =−2a(m1+m2+m3)3=0