If the normals at (xi,yi), i=1,2,3,4 on the rectangular hyperbola, xy=c2, meet at the point (α,β), Σxi=
A
α2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
α
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
β
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
β2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Bα Equation of normal to the rectangular hyperbola xy=c2 at t is given by, y−ct=t2(x−ct) ⇒ty=t3x−ct4+c Given it passes through (α,β) ⇒tβ=t3α−ct4+c⇒ct4−αt3+βt−c=0 ∴∑iti=αc Thus ∑ixi=∑icti=α Hence, option 'B' is correct.