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Question

If the normals at (xi,yi), where, i=1,2,3,4 on the rectangular hyperbola xy=c2 meet at (α,β). and x1x2x3x4=a and y1y2y3y4=b, then a+b is

A
α2+β2
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B
(α2+β2)
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C
2c4
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D
2c4
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Solution

The correct option is D 2c4
The equation of the normal to the hyperbola xy=c2 at (ct,ct) is
xt3ytct4+c=0
ct4xt3+ytc=0
which is passing through (α,β)
Thus, ct4αt3+βtc=0.
Let its four roots are t1,t2,t3,t4.
Therefore, t1+t2+t3+t4=αc,
(t1t2)=0,(t1t2t3)=βc
and (t1t2t3t4)=1.
x1x2x3x4=c4(t1t2t3t4)=c4
y1y2y3y4=c4(1t1t2t3t4)=c4(11)=c4
a+b=2c4

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