IF the nth term of an AP is (2n +1) then the sum of its first three terms is (a) 6n +3 (b) 15 (c) 12 (d) 21
The sum of first n terms of an AP is (4n2+2n) The nth term of this AP is (a) (6n-2) (b) (7n-3) (c) (8 n - 2) (d) (8n + 2)