Question

If the nuclide of actinium ${}_{89}A{c}^{228}$, emits $\beta$ particle, the daughter nuclide will be :

• A. ${}_{88}R{a}^{228}$
• B. ${}_{90}T{h}^{228}$
• C. ${}_{87}F{r}^{224}$
• D. ${}_{90}T{h}^{229}$

Answer 1

The correct option is B ${}_{90}T{h}^{228}$

${}_{89}^{228}Ac{\to }_{90}^{228}Th{+}_{-1}^0\beta$