Question

If the number 357y25x is divisible by both 3 and 5 then find the missing digit in the unit's place and the thousand place respectively are

• A. 0, 6
• B. 5, 6
• C. 5, 4
• D. None of these

Answer 1

The correct option is B 5, 6

Let the required number be 357y25x.
Then, for divisibility by 5, we must have x = 0 or x = 5.
Case I. When x = 0
Then, sum of digits = (22 + y). For divisibility by 3, (22 + y) must be divisible by 3.
$\therefore y=2or5or8$
$\therefore Numbersare(0,2)or(0,5)or(0,8)$
Case II. When x = 5.
Then, Sum of digits = (27 + y). For divisibility by 3, we must have y = 0 or 3 or 6 or 9.
$\therefore Numbersare(5,0)or(5,3)or(5,6)or(5,9)$