Question

If the number 41x is divisible by 9, then find the value of digit x.

• A. 4
• B. 5
• C. 3
• D. 6

Answer 1

The correct option is A

4

41x is divisible by 9.

Sum of digits 4 + 1 + x or 5 + x will be the multiple of 9.

5 + x can be equal to 0, 9, 18, ...

if 5 + x = 0 $\Rightarrow$ x = -5

x cannot be negative

if 5 + x = 9 $\Rightarrow$ x = 4

if 5 + x = 18 $\Rightarrow$ x = 13

x cannot be a number more than 9. Same is the case with values more than 18.

Hence x = 4